## How to find if parameter of a function divided by 2 is NaN?

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I am needing to write a function that takes in a parameter. If the parameter divided by 2 is NaN it is to return "FLYING NOCTURNAL MAMMAL MAN!" Otherwise it is to return the result of the parameter divided by 2. I feel like what I am trying is pretty close. Any help would be greatly appreciated! Thanks.

Here is what I am trying:

nananan = (num) => { if(num/2 == isNaN(num) || isNaN(num)) { return "FLYING NOCTURNAL MAMMAL MAN!"; } else { return num; } }

nan = (num) => { if (isNaN(num/2)) return "FLYING NOCTURNAL MAMMAL MAN!" else return num/2 } console.log(nan(2)) console.log(nan('a'))

**isNaN(),** The isNaN() function determines whether a value is NaN or not. function milliseconds(x) {. 2. if (isNaN(x)) {. 3. return 'Not a Number!'; For example, dividing zero by zero results in a NaN — but dividing other isNaN , the expression (x != x) is a more reliable way to test whether variable x is NaN or not, Similarly, nanf and nanl return NaN values of type float and long double, respectively. Parameters tagp An implementation-specific C-string. If this is an empty string (""), the function returns a generic NaN value (the same as returned by passing "NAN" to strtod). Return Value A quiet NaN value. See also isnan Is Not-A-Number (macro/function

so the following codes should work

nananan = (num) => { if(isNaN(num)) { return "FLYING NOCTURNAL MAMMAL MAN!"; } else { return num/2; } } console.log(nananan()); //now its NAN console.log(nananan('adf')); //now its NAN console.log(nananan(1)); //now its not a NAN console.log(nananan(-1)); //now its not a NAN

**NaN and Infinity in JavaScript,** About | Donate | Subscribe | Search | Archive | Books The value NaN in JavaScript stands for “not a number”. at your disposal, you have to use the global function isNaN() to detect it. > pitfall of isNaN(): It coerces its argument to number and will thus even Division by 0 gives you another special value: This function returns true if the value equates to NaN. Otherwise it returns false. This function is different from the Number specific Number.isNaN () method. The global isNaN () function, converts the tested value to a Number, then tests it. Number.isNaN () does not convert the values to a Number,

You can make this more concise using a conditional ternary `?`

operator:

const nananan = num => isNaN(num) ? 'FLYING NOCTURNAL MAMMAL MAN!' : num / 2;

As I mentioned in comments, while `isNaN(num / 2)`

is indeed the condition you were looking for, it is true if and only if `isNaN(num)`

is true.

**How can I fix the NaN error?,** will yield the value NaN (since trying to calculate atan(0/0) which has 0 divided by 0). The appearance of NaN in any variable calculations will make the results It doesn't work because Parameters!Parameter2.Value is actually an array because it is a multi-select parameter. So you're trying to convert an array to an integer and that won't work. You can even access individual array elements by doing Parameters!Parameter2.Value(1) or the number of items in the array Parameters!Parameter2.Count (more info)

**NaN in Typescript,** We can check whether a value is NaN by using the isNaN function or by Number. Converting an Invalid value to a number; Dividing Zero by Zero 1. 2. 3. 4. let v=undefined;. console.log(parseInt(v)); //NaN. Typescript throws compiler error here If the argument is not a number , then it results false . Can you post some sample data? Generally, if zeros are involved, use DIVIDE to avoid divide by zero errors. Additionally, use the erd parameter "alternateresult" option of the DIVIDE function to catch divide by zero and return what you want. Potentially wrap it all in an IF statement if necessary.-----

**isNaN(),** isNaN(), as defined in ECMAScript 6, or you can use typeof to determine if the value is For example, dividing zero by zero results in a NaN â€” but dividing other When the argument to the isNaN function is not of type Number, the value is is converted to 0 increment("1"); // 2: "1" is converted to 1 increment("0.1"); // 1.1: Given any numerical value, it can be classified into 3 different classes such as Finite Number, Infinite Number and Not a Number or commonly known as NaN. While developing a project that is highly dependent on User Inputs there might be many cases where the user provides inappropriate inputs while a function expects a finite numerical input thus creating an unhandled situation or unexpected result.

**Detect division by zero,** Write a function to detect a divide by zero error without checking if the denominator is zero. Contents. 1 8th; 2 ABAP; 3 Ada; 4 Aime; 5 ALGOL 68; 6 ALGOL W; 7 AutoHotkey You can use NOT ISVALID(x) to test if the value is a NaN. CheckForDivByZero(x/y) ' automatic conversion to type of parameter which is Integer Fill NA/NaN values using the specified method. Value to use to fill holes (e.g. 0), alternately a dict/Series/DataFrame of values specifying which value to use for each index (for a Series) or column (for a DataFrame). Values not in the dict/Series/DataFrame will not be filled. This value cannot be a list. Method to use for filling holes in

##### Comments

`isNaN(num / 2)`

?- The only way this would occur is if
`isNaN(num)`

itself was also true. - I'm not sure if this is a shitpost or I'm not seeing something here...
- @ChristopherFrancisco This may enlighten you. Skip to 3:30
- Clearly the function must be named
`nananan`

or it is not valid ;) (kidding, of course) - if my answer is correct, please mark it as the right answer so your question can be closed.
- @PatrickRoberts That's easy:
`4`

. In fact any number at all that isn't`NaN`

,`Infinity`

,`-Infinity`

,`0`

, or`-0`

. - Ah, that's the part you were fixated on... to be fair, that's not clear unless you're completely dismissing the attempted implementation.
- dear down voter can you please explain why down vote? so i can improve?
- It should return
`num/2`

in the else clause. - True, but he said it should "return the result of the parameter divided by 2". I'm pretty sure the original code didn't work at all and the OP thought that
`num/2`

in the if statement mutated`num`

, so that all future usage was already divided by 2.